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NIELIT Recruitment 2020 49 Scientist – B , Scientific Assistant posts | nielit delhi recruitment

Last updated on: December 3rd, 2020 at 3:15 pm
Edited by: Sathish Kumar

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NIELIT Recruitment 2020 | Various 49 Scientist – B , Scientific Assistant posts | Last date: 31-12-2020 | Apply Online @https://www.nielit.gov.in/

NIELIT Recruitment 2020: The National Institute of Electronics and Information Technology has been released a notification for 49 Scientist – B , Scientific Assistant Posts in All over India on 03-12-2020. The interested candidates who are looking for Central government can apply before the last date of the application.

Basic information about NIELIT recruitment 2020

Organization Name National Institute of Electronics and Information Technology
Job TypeCentral government
Total Vacancy49
Post NameScientist – B , Scientific Assistant
Location All over India
Starting Date 03-12-2020
Last date 31-12-2020
Websitehttps://www.nielit.gov.in/

Eligibility Criteria to Apply for NIELIT Recruitment 2020

Post nameNo of Posts
Scientist – B10
Scientific Assistant39

Education details

Post namePost Qualification
Scientist – BM.Sc(Electronics / CS ) / MCA / ME / M.Tech
Scientific AssistantM.Sc(Electronics / CS / IT / Physics / Applied Electronics) / MCA / BE / B.Tech

Age limit

Post nameAge limit details
Scientist – BUpto 30 years
Scientific AssistantUpto 30 years

Selection process

The NIELIT department will conduct the selection process by Written Exam .

Salary details

Post nameSalary details
Scientist – BRs.56,100 to Rs.1,77,500 Per Month
Scientific AssistantRs.35,400 to Rs.1,12,400 Per Month

Application modes

  • The candidates should apply the application via Online mode
  • Application fees will be charged Rs.800(General) & Rs.400(SC / ST / PWD / Women) .
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    Steps to Apply for NIELIT Recruitment 2020

    Steps to send your application in online:
    Go to the official site and read the notification
    Read the notification and check your eligibility status
    Find the online link above this line
    Enter your details and click submit and click the “submit button (Make payment) “


     Share this Job: Job is expired

    31-12-2020